Question

If the solubility of lithium sodium hexafluorido aluminate, Li3Na3 (AlF6)2 is ‘s’ mollt–1, its solubility product is equal to :

• A. 729 s8
• B. 12 s8
• C. 3900 s8
• D. 2916 s8

Answer 1

Answer: (D)

2916 s8

Answer 2

(1) Li3Na3(AlF6)2 $\longrightarrow$3Li+ + 3Na+ + 2[AlF6]3–

Ksp = (3s)3 (3s)3 (2s)2 = 2916 s8.