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Question

Chemistry Question on Equilibrium

If the solubility of Ag2CrO4Ag_2CrO_4 is S mole/litre.Then its solubility product is

A

S2S^2

B

S3S^3

C

4S34S^3

D

2S32S^3

Answer

4S34S^3

Explanation

Solution

Ag2CrO4<=>2Ag+2SCrO42sAg_{2}CrO_{4} {<=>} \underset{\text{2S}}{{2Ag^{+}}} \underset{\text{s}}{{CrO_{4}^{-2}}} Ksp=[Ag+]2[CrO42]=(2S)2(S)=4S3K_{sp}=[Ag^{+}]^{2} [CrO^{-2}_{4}] =(2S)^{2}(S)=4S^{3}