Question

If the slope of a line passing through the point A (3, 2) be 3/4, then the points on the line which are 5 units away from A, are.

• A. (5, 5), (– 1, – 1)
• B. (7, 5), (– 1, – 1)
• C. (5, 7), (– 1, – 1)
• D. (7, 5), (1, 1)

Answer 1

Answer: (B)

(7, 5), (– 1, – 1)

Answer 2

The equation of line passes through (3, 2) and of slope $\frac { 3 } { 4 }$ is $3 x - 4 y - 1 = 0$

Let the point be $( h , k )$then $3 h - 4 k - 1 = 0$ ……(i)

and $( h - 3 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 5 ^ { 2 }$ ……(ii)

On solving the equations, we get $h = - 1,7$ and $k = - 1,5$ . Hence points are (–1, –1) and (7, 5).