Question

If the sides of the triangle are 5K, 6K, 5K and radius of

incircle is 6 then value of K is equal to –

• A. 4
• B. 5
• C. 6
• D. 7

Answer 1

Answer: (A)

4

Answer 2

S = = $\frac { 5 k + 6 k + 5 k } { 2 }$ = 8k

D = $\sqrt { \mathrm { S } ( \mathrm { S } - \mathrm { a } ) ( \mathrm { S } - \mathrm { b } ) ( \mathrm { S } - \mathrm { C } ) } = \sqrt { 8 \mathrm {~K} \cdot 3 \mathrm {~K} \cdot 2 \mathrm {~K} \cdot 3 \mathrm {~K} }$

= 12 K²

given r = 6

\ 6 = ̃ 6 = ̃ K = 4