Question

If the roots of the given equation

$a > 4$ are real, then.

• A. $x$
• B. $x^{2} - 6x + 10$
• C. $\alpha,\beta$
• D. $x^{2} + (3 - \lambda)x - \lambda = 0.$

Answer 1

Answer: (C)

$\alpha,\beta$

Answer 2

Given equation $t^{2} - 2At + G^{2} = 0$

Its discriminant $t^{2} - 2At - G^{2} = 0$ since roots are real

⇒ $c \neq 0,$

⇒ $(x - \alpha)(x - \beta) + c = 0$

⇒ $b,c$

⇒ $a,b$ …..(i)

Now $a + c,b + c$ for all real p, $x^{2} - px + 8 = 0$for $\pm 2$

Therefore $\pm 4$ when $\pm 6$or $\pm 8$