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Question: If the roots of the equation \(x^{2} + x + 1 = 0\) are reciprocal to each other, then....

If the roots of the equation x2+x+1=0x^{2} + x + 1 = 0 are reciprocal to each other, then.

A

x2+xe−e=0x^{2} + xe - e = 0

B

x=6+6+6+....∞,x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ....\infty}},}

C

2<x<32 < x < 3

D

x=3x = 3

Answer

x2+xe−e=0x^{2} + xe - e = 0

Explanation

Solution

Given equation is (−∞,−1)( - \infty, - 1) and whose roots are x2+bx+c=0,x^{2} + bx + c = 0, and c<0<b,c < 0 < b, , then the product of roots is