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Question

Mathematics Question on Quadratic Equations

If the roots of the equation x2+ax+b=0x^2 + ax + b = 0 are cc and dd, then one of the roots of the equation x2+(2c+a)x+c2+ac+b=0x^{2}+\left(2c+a\right)x+c^{2}+ac+b=0 is

A

cc

B

dcd-c

C

2d2\,d

D

2c2\,c

Answer

dcd-c

Explanation

Solution

f(x)=x2+ax+bf(x)=x^{2}+a x+b, then
f(x+c)=(x+c)2+a(x+c)+bf(x+c)=(x+c)^{2}+a(x+c)+b
=x2+(2c+a)x+c2+ac+b=x^{2}+(2\,c+a) x+c^{2}+a c+b
which shows that the roots of f(x)f(x) are transformed to (xc)(x-c) i.e., roots of f(x+c)=0f(x+c)=0 are ccc-c and dcd-c.
Hence, one of the roots of the equation f(x+c)f(x+c) is (dc)(d-c).