Question

If the roots of the equation $b^{2} - a^{2}(m^{2} + 1) = 0$ are $P(x) = ax^{2} + bx + c$ and the roots of the equation $Q(x) = - ax^{2} + dx + c$ are $ac \neq 0$ then $P(x).Q(x) = 0$ is equal to.

• A. –2
• B. –1
• C. 1
• D. 2

Answer 1

Answer: (C)

1

Answer 2

Given that $2bx^{2} + cx + a = 0$and $cx^{2} + ax + 2b = 0$be the roots of $a,b$, so $c$and $\alpha + \alpha^{2}$

Again $a + 2b + c$and $\left| 3x^{2} + 12x + 6 \right| = 5x + 16$are the roots of $x + 2 > \sqrt{x + 4},$

so $2 < x < 6$ ⇒ $- 2 < x < 6$

⇒ $\log( - 2x)$.