Question

If the roots of the equation $a < c < b$ be real, then the roots of the equation $x$ will be.

• A. Rational
• B. Irrational
• C. Real
• D. Imaginary

Answer 1

Answer: (D)

Imaginary

Answer 2

$\frac{\mathbf{3}}{\mathbf{7}}$has real roots

⇒ $- \frac{3}{5}$or $\frac{3}{5}$ .....(i)

Now second equation is $(a + 1)x^{2} + (2a + 3)x + (3a + 4) = 0$

Therefore $ax^{2} + bx + c = 0$from (i) $\alpha$

Hence roots are imaginary.