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Question: If the roots of \((b - c)x^{2} + (c - a)x + (a - b) = 0\) are equal then \(a + c =\)...

If the roots of (bc)x2+(ca)x+(ab)=0(b - c)x^{2} + (c - a)x + (a - b) = 0 are equal then a+c=a + c =

A

2b

B

b2b^{2}

C

3b

D

b

Answer

2b

Explanation

Solution

bc+ca+ab=0b - c + c - a + a - b = 0

Hence one root is 1.Also as roots are equal, other root will also be equal to 1.

Also α.β=abbc\alpha.\beta = \frac{a - b}{b - c}1.1=abbc1.1 = \frac{a - b}{b - c}ab=bca - b = b - c2b=a+c2b = a + c