Question

If the roots of ax² + bx + c = 0 are a, b and the roots of Ax² + Bx + C = 0 are a – k, b – k then (B² – 4AC)/(b² – 4ac) is equal to –

• A. 0
• B. 1
• C. (A/a)²
• D. (a/A)²

Answer 1

Answer: (C)

(A/a)²

Answer 2

$|\alpha –\beta|$ = $\left| (\alpha –k)–(\beta –k) \right|$

$\frac{\sqrt{D_{1}}}{|a|}$ = $\frac{\sqrt{D_{2}}}{|A|}$

$\frac{D_{1}}{D_{2}}$ = $\frac{a^{2}}{A^{2}}$Ž $\frac{b^{2}–4ac}{B^{2}–4ac}$ = $\frac{a^{2}}{A^{2}}$

Ž $\frac{B^{2}–4AC}{b^{2}–4ac}$ = $\frac{A^{2}}{a^{2}}$