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Question: If the roots of a<sub>1</sub>x<sup>2</sup> + b<sub>1</sub>x + c<sub>1</sub> = 0 are a<sub>1</sub>, b...

If the roots of a1x2 + b1x + c1 = 0 are a1, b1, and those of a2x2 + b2x + c2 = 0 are a2, b2 such that a1a2 = b1b2 = 1 then-

A

a1a2\frac{a_{1}}{a_{2}}=b1b2\frac{b_{1}}{b_{2}}=c1c2\frac{c_{1}}{c_{2}}

B

a1c2\frac{a_{1}}{c_{2}}=b1b2\frac{b_{1}}{b_{2}}=c1a2\frac{c_{1}}{a_{2}}

C

a1a2 = b1b2 = c1c2

D

None of these

Answer

a1c2\frac{a_{1}}{c_{2}}=b1b2\frac{b_{1}}{b_{2}}=c1a2\frac{c_{1}}{a_{2}}

Explanation

Solution

Roots of the second equation are reciprocal of those of the first.

\ c1x2 + b1x + a1 = 0 and a2x2 + b2x + c2 = 0 have both roots