Question
Question: If the relative permeability of a medium is \({\mu _r}\) and its dielectric constant is \({\varepsil...
If the relative permeability of a medium is μr and its dielectric constant is εr then the velocity of light in that medium will be:
A. εrμr
B. εrμrc
C. μrεr/με0
D. μ0ε0/μrεr
Solution
Hint:- According to the question, firstly we have to discuss the formulae of velocity of light which is related with relative permeability and dielectric constant. Then, we will change the medium and calculate the velocity of that changed medium.
Complete step by step solution:-
Given that-
Relative permeability of a medium= μr
Dielectric Constant= εr
As we know that, the velocity of light is formulated by:
c=ε0μ01
here,
c is the velocity of light
ε0 is the dielectric constant for the velocity of light
μ0 is the permeability for the velocity of light.
Now, if we change the medium, then the velocity of medium is formulated as:
v=εμ1
(here,
ε is the dielectric constant for the change in medium
ε=ε0εr or
Dielectric Constant for change in medium=Dielectric constant for velocity of light- dielectric constant
And, μ is the relative permeability for the change in medium.
μ=μ0μr .)
∵v=ε0εrμ0μr1 =εrμrc
So, when we change the medium, then the velocity of that particular medium is εrμrc .
Hence, the correct option is (B.) εrμrc .
Note:- The dielectric constant and relative permittivity are vital to the activity of capacitors and the assurance of the degrees of capacitance reachable. Permittivity and dielectric steady are two terms that are vital to capacitor innovation. Frequently talk will be known about capacitors with various dielectrics being utilized.