Question

If the reaction sequence given below is carried out with 15 moles of acetylene, the amount of the product D formed (in g) is _____.

The yields of A, B, C and D are given in parentheses.
[Given : Atomic mass of H = 1, C = 12, O = 16, Cl = 35]

Answer 1

Molecular weight = $C_8H_8O_2$
= 12 x 8 + 1 x 8 + 16 x 2 = 96 + 8 + 32 = 136
Moles of product (D) formed
$\frac{15}{3}$ x 0.8 x 0.5 x 0.5 =$\frac{3}{3}$ = 1
∴ Weight of product (D) = 1 x 136 = 136 g