Question
Question: If the ratio of the specific heats of steam is 1.33 and R=8312 J/k mol K, find the molar heat capaci...
If the ratio of the specific heats of steam is 1.33 and R=8312 J/k mol K, find the molar heat capacities of steam at constant pressure and constant volume.
A.33.5 kJ/k mole, 25.19 kJ/k mole
B.25.19 kJ/k, 33.5 kJ/kg K
C.18.82 kJ/k, 10.82 kJ/mol K
D.None of these
Solution
In this question we have to find the specific heat capacities at constant volume and pressure. For this we are going to use Mayer’s formula and we will use the formula of the ratio of specific heats at constant volume and pressure.
Complete step by step answer:
Given,
CVCP=1.33
R=8312 J/k mole
Formulae used,
CVCP=γ….. (1)
CP−CV=R……. (2)
If we convert above formula to find the relation betweenCV, R and γ
CV=γ−1R…. (3)
Where,
CP is specific heat at constant pressure and
CV is specific heat at constant volume
Now, using given values to find CP and CV
R is gas constant
CV=γ−1R
CV=1.33−18312
So on doing the simplification,we have
CV=0.338312
CV=25187.87 J/k mole
CV=25.19 kJ/k mole
Now, using equation (2) to findCP, putting the value of CVin equation (2)
CP=R+CV
CP=8312+25187.87
And hence on solving, we have
CP=33499.87 J/k mole
CP=33.5 kJ/k mole
Result- Hence, from the above calculation the specific heat at constant volume is CV=25.19 kJ/k mol and CP=33.5 kJ/k mole.
Hence option (A) is correct.
Note:
In this question we have used two formulae of specific heat. So, the knowledge of these formulae is a must and we should be careful while doing the calculation of the problems. One more thing that we must be careful about is the units of parameters. All the units must be in the same system.
In this question it was quite easy that we just had to apply formula directly but there might be a case when we have to be careful when using the formulae because we might have to use some theoretical aspects before applying the relevant formula. By following these steps we can find the correct answer to the problem.