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Question: If the ratio of the ratio of the roots of l*x*<sup>2</sup> + µ*x* + v = 0 is equal to the ratio of t...

If the ratio of the ratio of the roots of lx2 + µx + v = 0 is equal to the ratio of the roots of x2 + x + 1 = 0 then l, µ, v are in –

A

A.P.

B

G.P.

C

H.P.

D

None of these

Answer

G.P.

Explanation

Solution

As ratio of roots for lx2 + µx + v = 0 and x2 + x + 1 = 0 are equal

\αβ\frac{\alpha}{\beta}= αβ\frac{\alpha'}{\beta'}, where a, b are roots of lx2 + mx + v = 0 and a¢, b¢ are roots of x2 + x + 1 = 0 gives by w and w2

\ αβ\frac{\alpha}{\beta}= ωω2\frac{\omega}{\omega^{2}}= 1ω\frac{1}{\omega} Ž b = wa

And a¢, b¢ are roots of x2 + x + 1 = 0, given by w and w2

\αβ\frac{\alpha}{\beta}= ωω2\frac{\omega}{\omega^{2}} = 1ω\frac{1}{\omega} Ž = wa

and a + b = – µλ\frac{µ}{\lambda}, ab = vλ\frac{v}{\lambda}

a (1 + w) = – μλ\frac{\mu}{\lambda}, α2\alpha^{2}w = vλ\frac{v}{\lambda}

Ž –aw2 = –µλ\frac{–µ}{\lambda}, a2w = vλ\frac{v}{\lambda}

Ž µ2λ2\frac{µ^{2}}{\lambda^{2}} = vλ\frac{v}{\lambda} or µ2 = lv.

Hence (2) is correct answer.