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Question

Question: If the ratio of specific heat of a gas at constant pressure to that at constant volume is \(\gamma\...

If the ratio of specific heat of a gas at constant pressure to that at constant volume is γ\gamma , the change in internal energy of a mass of gas, when the volume changes from V to 2V constant pressure p, is

A

R/(γ1)R / ( \gamma - 1 )

B

C

pV/(γ1)p V / ( \gamma - 1 )

D

Answer

pV/(γ1)p V / ( \gamma - 1 )

Explanation

Solution

ΔU=μCVΔT=n(Rγ1)ΔT\Delta U = \mu C _ { V } \Delta T = n \left( \frac { R } { \gamma - 1 } \right) \Delta T

ΔU=PΔV(γ1)=P(2VV)γ1=PV(γ1)\Rightarrow \Delta U = \frac { P \Delta V } { ( \gamma - 1 ) } = \frac { P ( 2 V - V ) } { \gamma - 1 } = \frac { P V } { ( \gamma - 1 ) }