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Question: If the ratio of masses of \(SO_{3}\)and \(O_{2}\)gases confined in a vessel is 1:1, then the ratio o...

If the ratio of masses of SO3SO_{3}and O2O_{2}gases confined in a vessel is 1:1, then the ratio of their partial pressures would be

A

5 : 2

B

2 : 5

C

2 : 1

D

1 : 2

Answer

2 : 5

Explanation

Solution

: Let m be the mass of SO3SO_{3}and O2O_{2}enclosed in the vessel.

Number of moles of SO3=m80SO_{3} = \frac{m}{80}

Number of moles of O2=m32O_{2} = \frac{m}{32}

Partial pressure of SO3,PA=m32×R×TVSO_{3},P_{A} = \frac{m}{32} \times \frac{R \times T}{V}

Partial pressure of O2,PB=m32×R×TVO_{2},P_{B} = \frac{m}{32} \times \frac{R \times T}{V}

Now, PAPB=m80×32m=25\frac{P_{A}}{P_{B}} = \frac{m}{80} \times \frac{32}{m} = \frac{2}{5}