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Question: If the ratio of amplitude of two waves is 4 : 3. Then the ratio of maximum and minimum intensity in ...

If the ratio of amplitude of two waves is 4 : 3. Then the ratio of maximum and minimum intensity in their interference will be –

A

16 : 18

B

18 : 16

C

49 : 1

D

1 : 49

Answer

49 : 1

Explanation

Solution

= (a1+a2)2(a1−a2)2\frac { \left( a _ { 1 } + a _ { 2 } \right) ^ { 2 } } { \left( a _ { 1 } - a _ { 2 } \right) ^ { 2 } }

= 491\frac { 49 } { 1 }