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Question

Chemistry Question on Chemical Kinetics

If the rate constant of a reaction has the value k=163×104(mol)12s1k=163 \times 10^{-4}( mol )^{-\frac{1}{2}} s ^{-1}, the order of the reaction is

A

one

B

two

C

zero

D

None of these

Answer

None of these

Explanation

Solution

Rate constant, k=1.63×104(mol)1/2s1k=1.63 \times 10^{-4}( mol )^{-1 / 2} s ^{-1}
For nth order reaction, k= Rate ( conc )n Conc.  time ×1( Conc )nk=\frac{\text { Rate }}{(\text { conc })^{n}} \frac{\text { Conc. }}{\text { time }} \times \frac{1}{(\text { Conc })^{n}}
SlSl units of concentration is molL1mol L^{-1} and time is ss.
Therefore, the units of k=mol1/2s1k= mol ^{-1 / 2} s ^{-1} cannot be possible.