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Question

Mathematics Question on Determinants

If the rank of the matrix [125 24a4 12a+1]\begin{bmatrix}-1 &2&5\\\ 2&-4&a-4\\\ 1&-2&a+1\end{bmatrix} is 1, then the value of aa is

A

-1

B

2

C

-6

D

4

Answer

-6

Explanation

Solution

Let
A=125 24a4 12a+1125 00a+6 00a+6A=\begin{vmatrix}-1&2&5\\\ 2&-4&a-4\\\ 1&-2&a+1\end{vmatrix}\sim\begin{vmatrix}-1&2&5\\\ 0&0&a+6\\\ 0&0&a+6\end{vmatrix}
[R2R2+2R1,R3R3+R1]\left[R_{2}\rightarrow R_{2}+2R_{1},R_{3}\rightarrow R_{3}+R_{1}\right]
clearly rank of A is 1 if a = -6