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Question: If the radius of the circumcircle of the triangle TPQ, where PQ is chord of contact corresponding to...

If the radius of the circumcircle of the triangle TPQ, where PQ is chord of contact corresponding to point T w.r.to circle x2 + y2 – 2x + 4y – 11 = 0, is 6 units, then minimum distance of T from the director circle of the given circle is

A

6

B

12

C

6 2\sqrt { 2 }

D

12 – 424 \sqrt { 2 }

Answer

12 – 424 \sqrt { 2 }

Explanation

Solution

(x – 1)2 + (y + 2)2 = 16

(x – 1)2 + (y + 2)2 = 32

Ž OS = 424 \sqrt { 2 }

\ required distance TS = OT – SO = 12 – 424 \sqrt { 2 }