Question

If the radius of $H$ is $0.53\, ?$, then what will be the radius of $_3Li^{2+}$ ?

• A. 0.17 ?
• B. 0.36 ?
• C. 0.53 ?
• D. 0.59 ?

Answer 1

Answer: (A)

0.17 ?

Answer 2

Radius of orbit $= \frac{n^{2}a_{0}}{z} \left(a_{0} = 0.529 \,? \right)$
Radius of $H = \frac{\left(1\right)^{2} \times 0.529 \,? }{1} = 0.53 \,?$
Thus, the radius of $_3Li^{2+}$ will be :
$= \frac{\left(1\right)^{2} \times0.529}{3} = 0.17 \,?$