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Question

Physics Question on Atoms

If the radius of first Bohr's orbit is x ,then de-Broglie wavelength of electron in 3rd orbit is nearly

A

2πx2 \pi x

B

6 π\pi x

C

9 x

D

x /3

Answer

6 π\pi x

Explanation

Solution

mνr=nh2π(r=r0n2Z)r0=xm \nu r = \frac{nh}{2 \pi } \left( r = \frac{r_0 n^2}{Z} \right) r_0 = x 2πr=nλλ=2πrn=6πx 2 \pi r = n \lambda \, \Rightarrow \, \lambda = \frac{2 \pi r}{n} = 6 \pi \, x