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Question: If the radius of earth contracts \(\frac { 1 } { n }\) of its present value, the length of the day w...

If the radius of earth contracts 1n\frac { 1 } { n } of its present value, the length of the day will be approximately

A

24nh\frac { 24 } { n } h

B

24n2h\frac { 24 } { n ^ { 2 } } h

C

24nh24 n h

D

24n2h24 n ^ { 2 } h

Answer

24n2h\frac { 24 } { n ^ { 2 } } h

Explanation

Solution

Conservation of angular momentum L=Iω=L = I \omega =

=25MR2×2πT== \frac { 2 } { 5 } M R ^ { 2 } \times \frac { 2 \pi } { T } = constant ∴ TR2T \propto R ^ { 2 }

[If M remains same]

T2T1=(R2R1)2\frac { T _ { 2 } } { T _ { 1 } } = \left( \frac { R _ { 2 } } { R _ { 1 } } \right) ^ { 2 } =(R/nR)2= \left( \frac { R / n } { R } \right) ^ { 2 } =1n2= \frac { 1 } { n ^ { 2 } }T2=24n2hrT _ { 2 } = \frac { 24 } { n ^ { 2 } } h r

[As].