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Question: If the radius of an octahedral void is r and radius of atoms in close packing is R, the relations be...

If the radius of an octahedral void is r and radius of atoms in close packing is R, the relations between r and R is

A

r=0.414Rr = 0.414R

B

R=0.414rR = 0.414r

C

r = 2R

D

r−2Rr - \sqrt{2}R

Answer

r=0.414Rr = 0.414R

Explanation

Solution

(2R)2=(R+r)2+(R+r)2(2R)^{2} = (R + r)^{2} + (R + r)^{2}

2R=R+r\sqrt{2}R = R + r

(2−1)R=r(\sqrt{2} - 1)R = r

0.414R=r0.414R = r