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Question

Mathematics Question on Rate of Change of Quantities

If the radius of a spherical balloon increases by 0.1%, then its volume increases approximately by

A

0.002

B

0.003

C

0.004

D

0.0005

Answer

0.003

Explanation

Solution

v=43πr2,Δr=(0.1100)rΔr=4πr2.(0.1100)r=(0.3100)vv = \frac{4}{3}\pi r^{2}, \,\because \,\Delta r = \left(\frac{0.1}{100}\right)r\,\therefore\,\Delta r = 4\pi r^{2}.\left(\frac{0.1}{100}\right)r = \left(\frac{0.3}{100}\right)v