Question

If the product of the roots of the equation

x² – 3kx + 2e^2lnk–1= 0is 7, then for real roots the value of k is

equal to :

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (B)

2

Answer 2

2e^2lnk – 1 = 7

e^2lnk = 4

k² = 4 , Ž k = 2, – 2

k = 2

because k must be positive