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Question

Question: If the probability of a horse A winning a race is 1/4 and the probability of a horse B winning the s...

If the probability of a horse A winning a race is 1/4 and the probability of a horse B winning the same race is 1/5, then the probability that either of them will win the race is

A

120\frac { 1 } { 20 }

B

920\frac { 9 } { 20 }

C

1120\frac { 11 } { 20 }

D

1920\frac { 19 } { 20 }

Answer

920\frac { 9 } { 20 }

Explanation

Solution

P(AB)=P(A)+P(B)=14+15=920P ( A \cup B ) = P ( A ) + P ( B ) = \frac { 1 } { 4 } + \frac { 1 } { 5 } = \frac { 9 } { 20 }

{Since events are mutually exclusive, so P(AB)=0}P ( A \cap B ) = 0 \}