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Question

Physics Question on kinetic theory

If the pressure and the volume of certain quantity of ideal gas are halved, then its temperature

A

is doubled

B

becomes one-fourth

C

remains constant

D

become four times

Answer

becomes one-fourth

Explanation

Solution

Ideal gas equal
pV=μRTp V=\mu R T
If pressure and the volume of certain quantity of ideal gas are halved
p2×V2=μR0T1\frac{p}{2} \times \frac{V}{2}=\mu R_{0} T_{1}
pV4=μRT1(R\frac{p V}{4} =\mu R T_{1} (\because R is constant ))
μRT4=μRT1\frac{\mu R T}{4} =\mu R T_{1}
T1=T4T_{1} =\frac{T}{4}
In this condition, temperature becomes one-fourth.