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Question

Question: If the pressure and the volume of certain quantity of ideal gas are halved, then its temperature...

If the pressure and the volume of certain quantity of ideal gas are halved, then its temperature

A

Is doubled

B

Becomes one-fourth

C

Remains constant

D

Become four times

Answer

Becomes one-fourth

Explanation

Solution

According to ideal gas law

P1V1T1=P2V2T2orT2=T1P2V2P1V1\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}orT_{2} = T_{1}\frac{P_{2}V_{2}}{P_{1}V_{1}}

Here, P1=P,V1=V,T1=TP_{1} = P,V_{1} = V,T_{1} = T

P2=P2,V2=V2,T2=?P_{2} = \frac{P}{2},V_{2} = \frac{V}{2},T_{2} = ?

T2=T(P2)(V2)PV\therefore T_{2} = \frac{T\left( \frac{P}{2} \right)\left( \frac{V}{2} \right)}{PV}

T2=T4T_{2} = \frac{T}{4}