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Question

Question: If the present units of length, time and mass (m, s, kg) are changed to 100m, 100s, and \(\frac{1}{1...

If the present units of length, time and mass (m, s, kg) are changed to 100m, 100s, and 110\frac{1}{10}kg then

A

The new unit of velocity is increased 10 times

B

The new unit of force is decreased 11000\frac{1}{1000} times

C

The new unit of energy is increased 10 times

D

The new unit of pressure is increased 1000 times

Answer

The new unit of force is decreased 11000\frac{1}{1000} times

Explanation

Solution

Unit of velocity = m/sec ; in new system =100m100secmsec\frac{100m}{100\sec\frac{m}{\sec}} (same)

Unit of force =kg×msec2= \frac{kg \times m}{\sec^{2}}; in new system

=110kg×100m100sec×100sec= \frac{1}{10}kg \times \frac{100m}{100\sec \times 100\sec} =11000kg×msec2= \frac{1}{1000}\frac{kg \times m}{\sec^{2}}

Unit of energy =kg×m2sec2= \frac{kg \times m^{2}}{\sec^{2}} ; in new system

=110kg×100m×100m100sec×100sec= \frac{1}{10}kg \times \frac{100m \times 100m}{100\sec \times 100\sec} =110kg×m2sec2= \frac{1}{10}\frac{kg \times m^{2}}{sec^{2}}

Unit of pressure =kgm×sec2= \frac{kg}{m \times \sec^{2}}; in new system

=110kg×1100m×1100sec×100sec=107kgm×sec2= \frac{1}{10}kg \times \frac{1}{100}m \times \frac{1}{100sec \times 100sec} = 10^{- 7}\frac{kg}{m \times sec^{2}}