Question

If the potential barrier across a p-n junction is 0.6 V. Then the electric field intensity, in the depletion region having the width of 6×10-6 m, will be ______× 105 N/C.

Answer 1

Electric field intensity
$E=\frac{V}{d}$
$\frac{0.6}{6 \times 10^{-6}}$
$= 1 \times 10^5$
So, the answer is 1.