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Question: If the position vectors of the points A, B, C, D be \(2\mathbf{i} + 3\mathbf{j} + 5\mathbf{k},\) \(\...

If the position vectors of the points A, B, C, D be 2i+3j+5k,2\mathbf{i} + 3\mathbf{j} + 5\mathbf{k}, i+2j+3k,5i+4j2k\mathbf{i} + 2\mathbf{j} + 3\mathbf{k}, - 5\mathbf{i} + 4\mathbf{j} - 2\mathbf{k} and i+10j+10k\mathbf{i} + 10\mathbf{j} + 10\mathbf{k} respectively, then

A

AB=CD\overset{\rightarrow}{AB} = \overset{\rightarrow}{CD}

B

ABCD\overset{\rightarrow}{AB}||\overset{\rightarrow}{CD}

C

ABCD\overset{\rightarrow}{AB}\bot\overset{\rightarrow}{CD}

D

None of these

Answer

ABCD\overset{\rightarrow}{AB}||\overset{\rightarrow}{CD}

Explanation

Solution

AB=ij2k\overset{\rightarrow}{AB} = - \mathbf{i} - \mathbf{j} - 2\mathbf{k} and CD=6i+6j+12k\overset{\rightarrow}{CD} = 6\mathbf{i} + 6\mathbf{j} + 12\mathbf{k}

Hence, ABCD.\overset{\rightarrow}{AB}||\overset{\rightarrow}{CD}.