If the pointegral (x, –1), (3, y), (–2, 3) and (–3, –2) be t... | MATH - POINTS RELATE TO TRIANGLE (ORTHOCENTRE,...) | SolveeIt | Solveeit

Today, August 18

Question

If the point (x, –1), (3, y), (–2, 3) and (–3, –2) be the vertices of a parallelogram, then-

A

x = 2, y = 4

B

x = 1, y = 2

C

x = 4, y = 2

D

None of these

Answer

x = 2, y = 4

Explanation

Solution

Mid Point of AC = mid point of BD

$\left( \frac{x - 2}{2},\frac{- 1 + 3}{2} \right)$ = $\left( \frac{3 - 3}{2},\frac{y - 2}{2} \right)$

(x, y) = (2, 4)