Question

If the plane $x - 3y + 5z = d$passes through the point (1,2,4), then the lengths of intercepts cut by it on the axes of x, y, z are respectively

• A. 15, –5, 3
• B. 1, –5, 3
• C. –15, 5, –3
• D. 1, –6, 20

Answer 1

Answer: (A)

15, –5, 3

Answer 2

If plane $x - 3 y + 5 z = d$ passes through point (1, 2, 4). Then $1 - 6 + 20 = d \Rightarrow d = 15$

Plane, $x - 3 y + 5 z = 15$ $\Rightarrow \frac { x } { 15 } + \frac { y } { - 5 } + \frac { z } { 3 } = 1$

Hence length of intercept cut by it on the axes (x, y, z) are respectively (15, – 5, 3)