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Question

Chemistry Question on Dual nature of matter

If the Planck?s constant h=6.6×10−34 Jsh = 6.6 \times 10^{-34} \, Js, the de Broglie wavelength of a particle having momentum of 3.3×10−24 kg ms−13.3 \times 10^{-24} \, kg \, ms^{-1} will be

A

0.002 ?

B

0.5 ?

C

2 ?

D

500 ?

Answer

2 ?

Explanation

Solution

λ=hp=6.6×10−343.3×10−24\lambda = \frac{h }{p } = \frac{6.6 \times10^{-34}}{3.3 \times10^{-24}}
=2×10−10m=2 ?= 2 \times10^{-10} m = 2 \,?