Question

If the oxygen (O₂) has root mean square velocity of C ms^–1, then root mean square velocity of the hydrogen (H₂) will be

• A. $Cms^{- 1}$
• B. $\frac{1}{C}ms^{- 1}$
• C. $4Cms^{- 1}$
• D. $\frac{C}{4}ms^{- 1}$

Answer 1

Answer: (C)

$4Cms^{- 1}$

Answer 2

$v_{rms} \propto \frac{1}{\sqrt{M}}$Ž$\frac{v_{O_{2}}}{v_{H_{2}}} = \sqrt{\frac{M_{H_{2}}}{M_{O_{2}}}}$Ž$\frac{C}{v_{H_{2}}} = \sqrt{\frac{2}{32}} = \frac{1}{4}$

Ž$v_{H_{2}} = 4Ccm/sec$