Question

If the odds in favour of winning a race by three horses are respectively 1:3; 1:4; 1:5, then the probability that one of these horse will win is

• A. 1/60
• B. 37/60
• C. 33/60
• D. None

Answer 1

Answer: (B)

37/60

Answer 2

If odds in favour of an event =

P(5) =

Thus probability of winning of three horses are ¼, 1/5 and 1/6 respectively. Clearly, they are mutually exclusive events.

∴ Required probability = $\frac { 1 } { 4 } + \frac { 1 } { 5 } + \frac { 1 } { 6 } = \frac { 37 } { 60 }$