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Question: If the numerator of a fraction is increased by 25% and the denominator decreased by 20% the new valu...

If the numerator of a fraction is increased by 25% and the denominator decreased by 20% the new value is 54\dfrac{5}{4}. What was the original fraction?
[a] 35\dfrac{3}{5}
[b] 45\dfrac{4}{5}
[c] 78\dfrac{7}{8}
[d] 37\dfrac{3}{7}

Explanation

Solution

Hint: Assume that the numerator of the original fraction is x and the denominator of the original fraction is y. Hence find the numerator and denominator of the new fraction in terms of x and y. Compare the new numerator to be equal to 5k and the new denominator to be equal to 4k. Hence find the value of x and y in k. Hence find the original fraction.

Complete step-by-step answer:

Let the numerator of the original fraction be x, and the denominator of the original fraction be y.
Since the numerator of the new fraction is increased by 25%
Hence, we have
The numerator of the new fraction =x+25100×x=1.25x=x+\dfrac{25}{100}\times x=1.25x
Since the denominator of the new fraction is decreased by 20%
Hence, we have
The denominator of the new fraction =y20100y=0.8x=y-\dfrac{20}{100}y=0.8x
Hence, we have 1.25x:08y::5:41.25x:08y::5:4
Here extremes are 1.25x and 4, and the means are 0.8y and 5
Since the product of means is equal to the product of extremes, we have
(1.25x)×4=0.8y×55x=4y\left( 1.25x \right)\times 4=0.8y\times 5\Rightarrow 5x=4y
Dividing both sides by 5, we get
x=4y5x=\dfrac{4y}{5}
Dividing both sides by y, we get
xy=45\dfrac{x}{y}=\dfrac{4}{5}
Hence the original fraction is 45\dfrac{4}{5}
Hence option [b] is correct.

Note: Verification:
The numerator of the original fraction = 4
Hence the numerator of the new fraction =4+25100×4=4+1=5=4+\dfrac{25}{100}\times 4=4+1=5
The denominator of the original fraction = 5
Hence, the denominator of the new fraction =520100×5=51=4=5-\dfrac{20}{100}\times 5=5-1=4
Hence, the fraction =54=\dfrac{5}{4}
Hence our answer is verified to be correct.