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Question

Quantitative Aptitude Question on Percentages

If the numerator of a fraction is increased by 200% and the denominator is increased by 300%, the resultant fraction is512\frac{5}{12}. What was the original fraction?

A

129\frac{12}{9}

B

59\frac{5}{9}

C

115\frac{11}{5}

D

95\frac{9}{5}

E

None of these

Answer

59\frac{5}{9}

Explanation

Solution

Let the original fraction be represented as xy\frac{x}{y}.

  • Increasing the numerator by 200% means it becomes x + 2x = 3x
  • Increasing the denominator by 300% means it becomes y + 3y = 4y
  • The new fraction is3x4y\frac{3x}{4y}, and we know this equals 512\frac{5}{12}.
    So,3x4y\frac{3x}{4y}= 512\frac{5}{12}
    Now we need to find the original fraction x/y that satisfies this equation. Let's look at the options and see which one works.
  • Option (1):129\frac{12}{9}
  • If we increase the numerator by 200%, we get 3*12 = 36
  • If we increase the denominator by 300%, we get 4*9 = 36
  • The new fraction would be3636\frac{36}{36}= 1, which is not512\frac{5}{12}. So this is incorrect.
  • Option (2): 59\frac{5}{9}
  • Increased numerator: 3*5 = 15
  • Increased denominator: 4*9 = 36
  • New fraction:1536\frac{15}{36}=512\frac{5}{12}. This matches the given information!
    Therefore, the original fraction was59\frac{5}{9}.
    Final Answer: (2) 59\frac{5}{9}
    The Correct option is(B)