Question
Question: If the normal to y<sup>2</sup> = 12x at (3, 6) meets the parabola again in (27, -18) and the circle ...
If the normal to y2 = 12x at (3, 6) meets the parabola again in (27, -18) and the circle on the normal chord as diameter is
A
x2 + y2 + 30x + 12y – 27 = 0
B
x2 + y2 + 30x + 12y + 27 = 0
C
x2 + y2 – 30x – 12y – 27 = 0
D
x2 + y2 – 30x + 12y – 27 = 0
Answer
x2 + y2 – 30x + 12y – 27 = 0
Explanation
Solution
According to question, equation of circle with points
(3, 6) and (27, -18) on diameter will be
(x-3)(x-27)+(y-6)(y+18) = 0
x2 + y2 – 30x + 12y – 27 = 0