Question

If the molecular wt. of $Na_2S_2O_3$ and $I_2$ are $M_1$ and $M_2$ respectively, then what will be the equivalent wt. of $Na_2S_2O_3$ and $I_2$ in the following reaction? $\ce{2S2O^{2-}_3 + I2-> S4O^{2-}_6 + 2I-}$

• A. $M_1, M_2$
• B. $M_1, M_2/2$
• C. $2M_1, M_2$
• D. $M_1, 2M_2$

Answer 1

Answer: (B)

$M_1, M_2/2$

Answer 2

$\therefore$ Equivalent mass of $S_2O_3^{2-} = \frac{M_1}{1} = M_1$
and equivalent mass of $I_2 = \frac{M_2}{2}$