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Question

Mathematics Question on Continuity and differentiability

If the minimum value of f(x)=5x22+αx5,x>0f(x)=\frac{5 x^2}{2}+\frac{\alpha}{x^5}, x>0, is 14 , then the value of α\alpha is equal to:

A

32

B

64

C

128

D

256

Answer

128

Explanation

Solution

The correct option will be (C): 128