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Chemistry Question on Thermodynamics terms

If the melting point of ice is 0?C0^?C and latent heat of fusion is 5.46 kJ mol−15.46\, kJ\, mol^{-1}, the entropy change for the conversion of 18 g18\, g of ice to water at one atmosphere is

A

5.46 J mol−1 K−15.46\, J \,mol^{-1}\, K^{-1}

B

20 J mol−1 K−120\, J \,mol^{-1}\, K^{-1}

C

50 J mol−1 K−150\, J \,mol^{-1}\, K^{-1}

D

360 J mol−1 K−1360\, J \,mol^{-1}\, K^{-1}

Answer

20 J mol−1 K−120\, J \,mol^{-1}\, K^{-1}

Explanation

Solution

ΔSf=ΔHfTm.p.\Delta S_{f} =\frac{\Delta H_{f}}{T_{m.p.}} =5.46×1000273=\frac{5.46\times1000}{273} =20 J mol−1 K−1=20\, J \,mol^{-1}\,K^{-1}