Solveeit Logo

Question

Mathematics Question on Median of Grouped Data

If the median of the distribution given below is 28.5, find the values of x and y.Class intervalFrequency
0 - 105
10 - 20x
20 - 3020
30 - 4015
40 - 50y
50 - 605
Total60
Answer

The cumulative frequency for the given data is calculated as follows.

Class intervalFrequencyCumulative frequency
0 - 1055
10 - 20x5 + x
20 - 302025 + x
30 - 401540 + x
40 - 50y40 + x +y
50 - 60545 + x +y
Total60

From the table, it can be observed that n = 60

45 + x + y = 60 or x + y = 15 ……………………….(1)
Median of the data is given as 28.5 which lies in interval 20 − 30.

Therefore, median class = 20 − 30
Lower limit (ll) of median class = 20
Cumulative frequency (cfcf) of class preceding the median class = 5 + x
Frequency (ff) of median class = 20
Class size (hh) = 10

Median = l+(n2cff)×hl + (\frac{\frac{n}2 - cf}{f})\times h

28.5 = 20+[602(5+x)20]×1020 + [\frac{\frac{60}2 - (5 +x)}{20}]\times 10

8.5 = (25x2)(\frac{25 - x}2)

17 = 25 - x
x = 8

From equation (1),
8 + y = 15
y = 7

Hence, the values of x and y are 8 and 7 respectively.