Question

If the mean free path of gaseous molecules is 60 cm at a pressure of 1 × 10^–4 mm Hg, what will be its mean free-path when the pressure is increased by 100 times ?

• A. 6.0 × 10^–1 cm
• B. 6.0 cm
• C. 6.0 × 10¹ cm
• D. 6.0 × 10² cm

Answer 1

Answer: (A)

6.0 × 10^–1 cm

Answer 2

l µ $\frac{T}{P}$

$\frac{\lambda_{2}}{\lambda_{1}}$= $\frac{P_{1}}{P_{2}}$

l₂ = 60 × $\frac{1}{100}$ = 0.6