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Question: If the matrices A, B, (A + B) are non-singular, then [A (A + B)<sup>–1</sup> B]<sup>–1</sup>, is eq...

If the matrices A, B, (A + B) are non-singular, then

[A (A + B)–1 B]–1, is equal to –

A

A + B

B

A–1 + B–1

C

A (A + B)–1

D

None of these

Answer

A–1 + B–1

Explanation

Solution

We have

[A (A + B)–1 B]–1 = B–1 ((A + B)–1)–1 A–1

= B–1(A + B)A–1 = (B–1 A + I) A–1

= B–1 I + IA–1 = B–1 + A–1.

Hence (2) is correct answer.