Question

If the M.S.D of a reading is 81 and the pitch of the scale is $0.05\;{\rm{cm}}$ than the main scale reading is:
A. $40.5\;{\rm{cm}}$
B. $4.05\;{\rm{cm}}$
C. $4.1\;{\rm{cm}}$
D. $0.45\;{\rm{cm}}$

Answer 1

The above can be resolved by using, the formula for the main scale reading is to be applied. The main scale reading for the measurement is equivalent to the product of the main scale division and the pitch of the calliper. The main scale is the large scale mounted on the vernier calliper that is graduated with the numerical values of the measurement, either in terms of the centimetres, millimetres or the inches. Moreover, the two adjacent markings over the calliper are dented utilizing terms known as the main scale division; this is also known as the vernier scale division

Complete step by step answer:
The expression for the main scale reading is,
$MSR = MSD \times p$
Here, MSR denotes the main scale reading, MSD main scale division and p denotes the pitch.
Substituting the values in above equation as,

MSR = MSD \times p\\\ MSR = 81 \times 0.05\;{\rm{cm}}\\\ MSR = 4.05\;{\rm{cm}} \end{array}$$ Therefore, the main scale reading is 4.05 cm **So, the correct answer is “Option B”.** **Note:** To resolve the given problem, one must be aware of the fundamental terms related with the measurement using the vernier scale, and the vernier scale is used to measure out the depth of any object, primarily with the outer as well as the inner dimensions. Moreover, the knowledge of the variables related to the measure like pitch, main scale reading and main scale division is also being applied to resolve such typical measurements. Furthermore, the vernier scale finds its various laboratory applications for the measurement of the typical dimensions.