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Question

Question: If the lines of regression are \(3x + 12y = 19\) and \(3y + 9x = 46\) then \(r_{xy}\)will be...

If the lines of regression are 3x+12y=193x + 12y = 19 and 3y+9x=463y + 9x = 46 then rxyr_{xy}will be

A

0.289

B

– 0.289

C

0.209

D

None of these

Answer

– 0.289

Explanation

Solution

rxy=(312)(39)=0.289r_{xy} = \sqrt{\left( \frac{- 3}{12} \right)\left( \frac{- 3}{9} \right)} = - 0.289.